Question

 2(3x+1)+3(1-2x)=
 3(x^{2}-2x-2)+x(6-3x)=
 x*x+x+x:x= (*=ori)
 (2\sqrt{2}*x)^{2}:(3x^{2})
 

Answer 1

2(3x+1)+3(1-2x)=6x+2+3-6x=0
5=0
nu are solutii
x∈Ф

3(x²-2x-2)+x(6-3x)=
3x²-6x-6+6x-3x²=0
nu are solutii
x∈Ф

x·x+x+x:x= 
x²+x+1=0
Δ=1-4=-3
Δ<0