Question

2(3x+1)+3(1-2x)=
xxx+x+x:x=
(x-2)(x+2)+4=
(x+4)(x-3)-x+12=
3(xla a 2-2x-2)+x(6-3x)=
(x-2)(x+3)-(x+3)la a 2+3(2x+7)=
Xla a 2-7x+5(x+8)(x-1)=
suma a doua nr naturale nu depaseste 120.Aflati nr stind ca prin impartirea celui mai mare la cel mai mic obtinem catul 9 restul 10.
repede va rog.

Answer 1

6x+2+3-6x=5
5x:x=5
x ²-2x+2x-4+4=x²
x²+4x-3x-12-x+12=x²
a+b<120
a:b=9rest10→a=9b+10
9b+10+b=120→10b+10=120→
b=11. a=11×9+10. a=109