Question

2^3x+ 4^x *2^x+2 +8^x+1=832

Answer 1

${2}^{3x} + {4}^{x} \times {2}^{x + 2} + {8}^{x + 1} = 832$
${2}^{3x} + {2}^{2x} \times {2}^{x + 2} + {2}^{3x + 3} = 832$
${2}^{3x} + {2}^{2x + x + 2} + {2}^{3x + 3} = 832$
${2}^{3x} (1 + 4 + 8) = 832$
${2}^{3x} \times 13 = 832$
${2}^{3x} = 832 \div 13 = 64$
${2}^{3x} = {2}^{6}$
3x = 6 => x = 2