Question

2+4+6+...+1000 nu este p.p (pătrat perfect)
ajutatima!

Answer 1

$\displaystyle 2+4+6+...+1000=2(1+2+3+...+500)=2 \cdot \frac{500(500+1)}{2} = \\ \\ =2 \cdot \frac{500 \cdot 501}{2} =\not 2 \cdot \frac{250500}{\not 2} =250500 \not=p.p$