Question

(2+4+6+...+200 )/(4+8+12+...+400)=

Answer 1

[2x(1+2+....+100)] : [4x(1+2+....+100)] =
(2x100x101:2) : (4x100x101:2) =
10100 : (2x10100)=
10100 : 20200 = 0,5

Answer 2

$\frac{2+4+6+...+200}{4+8+12+..+400}=\frac{2*(1+2+3+...+100)}{4*(1+2+3+...+100)}=\frac{2}{4}=0,5$