Question

{2^4+7×[31+10×(3^7÷3^5+3^2÷3^1)-49]}÷73 cat face ?.

Answer 1

Răspuns:

10

Explicație pas cu pas:

{2^4+7x[ 31+10x (9+3) -49]} :73 =

[2^4+7x( 31+120-49)]:73=

(2^4+714):73=

730:73= 10

Answer 2

Răspuns:

10

Explicație pas cu pas:

$\{2^4 + 7 \times [31 + 10 \times (3^7 \div 3^5 + 3^2 \div 3^1) - 49] \} \div 73$

$= \{16 + 7 \times [31+10 \times (3^2 + 3) - 49] \} \div 73$

$= \{16 + 7 \times [31 + 10 \times (9 + 3) - 49] \} \div 73$

$= [16 + 7 \times (31 + 10 \times 12 - 49)] \div 73$

$= [16 + 7 \times (31 + 120 - 49)] \div 73$

$= (16 + 7 \times 102) \div 73$

$= (16 + 714) \div 73$

$= 730 \div 73$

$= \bf 10$