Question

2,4g de magneziu se supune arderii.cati moli de oxid bazic se obtin. si ce cantiate de oxigen avem nevoie

Answer 1

Răspuns:

calculam in grame:

MMg=24g/mol

MO2=2×16=32g/mol

MMgO=24+16=40g/mol

2×24g....32g....2×40g

2Mg  +  O2  → 2MgO

2,4g.......xg.......yg

x=2,4×32/2×24=calculeaza

y=2,4×2×40/2×24=calculeaza

calculam in moli

n=m/M=2,4/24=0,1moli Mg

2moli......1mol.......2moli

2Mg  +  O2    →   2MgO

0,1moli....zmoli......tmoli

z=0,1×1/2= calculeaza

t=0,1×2/2 = calculeaza

Explicație: