Question

{[(2^5^2013^0+3^0^13^2013+7^1^11^2013):5^1^9^2013]:2^2013:2^2013}​

Answer 1

$2^5+1+7=32+8=40$

deoarece 0 la orice putere e 0 , iar orice numar ridicat la 0 e egal cu 1.

si 1 la orice putere e egal tot cu 1. in rest s-au calculat la rand puterile .

$2^{5^{2013^{0}}}=2^{5^{1}}=2^5\\3^{0^{13^{2013}}}=3^0=1\\7^{1^{11^{2013}}}=7^1=7$