Question

2) 53 ⁺ 368 : ( 1463 : 7- 1608 : 8 ) ⁺ 1 = ?

4) b¹³ ·b ·b²¹·b²° = ?

5) 16⁴ ·4¹°·64⁵ = ?

6) c⁵⁸ c³⁹ c⁹ = ?

7) ( 8 ³⁷ ·81 ²⁵ ) : ( 16 ²⁷·27 ³³) = ?


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Answer 1

$a). 53+368:(1463:7-1608:8)+1=53+368:(209-201)+1= \\ =53+368:8+1=53+46+1=99+1=100 \\ b).b^{13} \cdot b \cdot b^2^1 \cdot b^2^0=b^{13+1+21+20}=b^{55} \\ c).16^4 \cdot 4^1^0 \cdot 64^5=(4^2)^4 \cdot 4^1^0 \cdot (4^3)^5=4^8 \cdot 4^1^0 \cdot 4^1^5=4^{8+10+15}=8^3^3 \\ d).c^{58}:c^{39}:c^9=c^{58-39-9}=c^1^0 \\ d).(8^3^7 \cdot 81^2^5):(16^2^7 \cdot 27^3^3)=[(2^3)^3^7 \cdot (3^4)^2^5]:[(2^4)^2^7 \cdot (3^3)^3^3]= \\ =(2^1^1^1 \cdot 3^{100}):(2^{108} \cdot 3^9^9)=2^3 \cdot 3=8 \cdot 3=24$