Question

2·6,023·10^{23} atomi vor fi in x g Ca, y g H si z g Cl. Ce valori vor avea x, y, z?

Answer 1

A Ca= 40 g 40g Ca.....6,022·10{23} atomi Xg Ca......2·6.022·10{23} atomi 40/1=6,022·10{23}/2·6,022·10{23}=>x=80g A H=1g 1g......6,022·10{23}atomi Yg....2·6,022·10{23}atomi 1/y22·10{23}/2·6,022·10{23}=> y=2g A Cl=35,5 g 35,5g Cl.....6,022·10{23}atomi Z g Cl.......2·6,022·10{23} atomi 35,5/z=6,022·10{23}/2·6,022·10{23} atomi=> z=71 g Spre ca te-am ajutat!