Question

[(2^6)^4:2^3*(2^6+2^6)-4^6:2^10]:(2^28-2^2)+9=

Answer 1

Răspuns:

Explicație pas cu pas:

[(2^6)^4:2^3×(2^6+2^6)-4^6:2^10]:(2^28-2^2)+9=

=[2^24:2^3×2^6(2^0+2^0)-2^12:2^10]:(2^28-2^2)+9=

=[2^21×2^6(1+1)-2^2]:(2^28-2^2)+9=

=(2^21×2^7-2^2):(2^28-2^2)+9=

=(2^28-2^2):(2^28-2^2)+9=

=1+9=10