Question

[(2^6)^4:2^3•(2^6+2^6)-4^6:2^10]:(2^28-2^2)+9


Va rog ajutati ma!!! Dau coroana...

Answer 1

Răspuns:

Explicație pas cu pas:

a^n x a^m = a^n+m

a^n : a^m = a^n-m

(a^n)^m=a^nxm

[(2^6)^4:2^3•(2^6+2^6)-4^6:2^10]:(2^28-2^2)+9=

[2^24:2^3•2·2^6)-(2^2)^6:2^10]:(2^28-2^2)+9=

[(2^24-3)•(2^1+6))-2^12:2^10]:(2^28-2^2)+9=

[2^21•2^7-(2^12-10)]:(2^28-2^2)+9=

[(2^21-7)-(2^12-10)]:(2^28-2^2)+9=

(2^28-2^2):(2^28-2^2)+9=

1+9=

10