Question

(2^64 -2^63 - 2^62 - 2^60):(2^4)^15 - (3^7)^0

Answer 1

$(2^6^4-2^6^3-2^6^2):(2^4)^1^5-(3^7)^0=2^6^2(1^2-1^1-1):2^6^0-1= \\ =1-1-1+2^2-1=-1+4-1=3-1=2$