Question

2 7supra12+51supra4 transformata

Answer 1

$2 \frac{7}{12}+ \frac{51}{4}= \frac{31}{12}+ \frac{51}{4} = \frac{31}{12}+ \frac{153}{12}= \frac{184}{12}= \frac{46}{3}=15 \frac{1}{3}$