Question

2^8^2÷2^2^4×(3^2-1)-3^0×2^2

Answer 1

(2^8)^2÷2^2^4×(3^2-1)-3^0×2^2 =
=2^16÷2^16×(9-1)-1×2^2 =
=1×2^3-2^2 =
=2^2(2-1) =
=2^2=4

Answer 2

[tex]=(2^8)^2:2^2^4*(3^2-1)-3^0*2^2 \\ =2^{16}:2^{16}*(9-1)-1*2^2 \\ =1*2^3-2^2\\ =2^2*(2-1) \\ =2^2\\ =4[/tex]