Question

2,8+(3- radical din 6 - 5,8)

Answer 1

$2,8 + (3- \sqrt{6}-5,8)= \\ \frac{14}{5}+(3- \sqrt{6}- \frac{29}{5})= \\ \frac{14+15-5 \sqrt{6}-29}{5} = \frac{-5 \sqrt{6} }{5}= -\sqrt{6}$

/robertinni