Question

2√8-5√32+4√2=?
4√3+12=?
5√2+√8=?
0.75√72-√2:2+0,8(3)√8=?

Answer 1

2*2√2-5*4√2+4√2=4√2-20√2+4√2= √2(4-20+4)= -12√2

4√3+12=4√3+12
daca e 4√3+√12, atunci 4√3+2√3=6√3


5√2+2√2=7√2


(3/4)*6√2-√2/2+(5/6)*2√2=(9/2)*√2-√2/2+(5/3)*√2=4√2+(5/3)√2=√2(4+5/3)=
=(17/3)*√2

Answer 2

[tex]\it 2\sqrt8-5\sqrt{32} +4\sqrt2 =2\sqrt{4\cdot2} -5\sqrt{16\cdot2} +4\sqrt2= \\\;\\ =4\sqrt2 -20\sqrt2+4\sqrt2=8\sqrt2-20\sqrt2=-12\sqrt2[/tex]


$\it 5\sqrt2+\sqrt8 =5\sqrt2 +\sqrt{4\cdot2} =5\sqrt2 +2\sqrt2 =7\sqrt2$


[tex]\it 0,75\sqrt{72} -\sqrt2:2+0,8(3)\sqrt8= 0,75\sqrt{36\cdot2} -\dfrac{\sqrt2}{2}+\dfrac{83-8}{90}\sqrt{8}= \\\;\\ \\\;\\ =\dfrac{3}{4}\cdot6\sqrt2-\dfrac{\sqrt2}{2}+\dfrac{75}{90}\cdot2\sqrt2= \sqrt2\left(\dfrac{9}{2}-\dfrac{1}{2}+\dfrac{5}{3}\right) =\dfrac{17\sqrt2}{3} [/tex]