Question

(2^86+2^86+2^87):2^80 Cum se rezolva?

Answer 1

$(2^{86}+2^{86}+2&{87}):2^{80} =\\ =2^{86}(1+1+2)\,:\,2^{80}=\\ =2^{86-80}\cdot4=2^6\cdot2^2=2^8$

Answer 2

Trimit rezolvarea in atach.