Question

(2-8supar X-2) inparit la x patrat -4x+4 supara x patrat -4

Answer 1

$(\frac{2-8}{x-2} ): \frac{ x^{2} -4x+4}{ x^{2} -4} = (-\frac{6}{x-2} ): \frac{(x-2)^2}{(x+2)(x-2)} =(- \frac{6}{x-2} )* \frac{(x+2)(x-2)}{(x-2)^2}$
se observa cu usurinta ca se simplifica pe diagonala (x-2). dupa simplificare va ramane:
$(-6)* \frac{x+2}{(x-2)^2} =- \frac{6(x+2)}{(x-2)^2}$