Question

2. Aluminiul reactioneaza cu Clorul obtinandu-se 120g Clorura de Aluminiu.
Calculati in grame si moli cantitatea de Aluminiu necesara

Answer 1

A,Al= 27g/mol

M,AlCl3=( 27gAl+ 3x35,5gCl)/mol= 133,5 g/mol

2mol....................2mol

2Al + 3Cl2---> 2AlCl3     sau,in grame

2x27g................2x133,5g

x.................................120

x= 120x27/133,5=..........................gAl        ..calculeaza !!!!