Question

2.Calculati :
a) (3,479+1,021)*1,(3) + 41,273 la puterea 0 ;
b) [( 2/5) la puterea 3]la puterea a 4 : [( 0,4) la puterea a 2 ] + 4,84 ;
Va rog mult  ajutati ma ?!!! dc nu ma ajutati si pe  mn  eu fac tot  posibilul sa va ajut .. am o profesoara foarte  rea daca nu ti faci tema iti pune  direct in catalog 3 :(((((( 

Answer 1

la primul:
4,5*1 intreg si 3/9+1=
4,5*12/9+ 1=
52,5/9+1/9=53,5/9=5,9(4)
al doilea e gresit...cred

Answer 2

[tex]a) 4,5*1,(3)+1= [/tex]
$=4 \frac{5}{10}+1 \frac{3}{9} =$
[tex]=4 \frac{1}{2} +1 \frac{1}{3}= [/tex]
$= \frac{9}{2}+ \frac{4}{3}=$
[tex]= \frac{27}{6}+ \frac{8}{6}= [/tex]
$= \frac{35}{6}$

$b) (\frac{2}{5})^{12}: (\frac{4}{10})^2+4 \frac{84}{100} =$
[tex]=( \frac{2}{5})^{12}: (\frac{2}{5})^2+4 \frac{21}{25} = [/tex]
[tex]= (\frac{2}{5})^{12}* \frac{25}{4}+ \frac{121}{25}= [/tex]
$= (\frac{2}{5})^{10}= \frac{2^{10}}{5^{10}}$