Question

2. Calculaţi x din proporţiile:

2 va rog dau coroana

Answer 1

Explicație pas cu pas:

a)

$\dfrac{x - 1}{1 + \dfrac{1}{2} } = \dfrac{ \dfrac{7}{3} - 1}{3 - \dfrac{3}{2} } \iff \dfrac{x - 1}{\dfrac{2 + 1}{2} } = \dfrac{ \dfrac{7 - 3}{3}}{\dfrac{6 - 3}{2} }$

$\dfrac{2(x - 1)}{3} = \dfrac{ \dfrac{4}{3}}{\dfrac{3}{2} } \iff \dfrac{2(x - 1)}{3} = \dfrac{4 \cdot 2}{3 \cdot 3}$

$\dfrac{2(x - 1)}{3} = \dfrac{8}{9} \iff 18(x - 1) = 24$

$x - 1 = \dfrac{4}{3} \iff x = \dfrac{4}{3} + 1 \\ \implies x = \dfrac{7}{3}$

b)

$\dfrac{2x + 1}{4x + 3} = \dfrac{1}{3} \iff 3(2x + 1) = 4x + 3 \\ 6x + 3 = 4x + 3 \iff 6x - 4x = 3 - 3 \\ 2x = 0 \implies x = 0$