Question

2.Ce numar de particule contin:
a)0,01 Kmoli CO
b)0,224 dm cubi O2
c)2 Kg C2H2(acetilena)

Answer 1

Inainte de a rezolva trebuie sa stii ca 1 mol de substanta este egal cu NA-nr lui Avogadro, care este egal cu 6,023*10^23 particule

a) 1 kmol = 1000 moli

0,01 kmoli = 10 moli CO

1 mol CO.....................6,023*10^23 particule
10 moli CO.................x=6,023*10^24 particule

b) 1dm3=1L

n=V/Vm=0,224/22,4=0,01 moli O2

1 mol O2.....................6,023*10^23 particule
0,01 moli O2...............x=6,023*10^21 particule

c) MC2H2=2AC+2AH=2*12+2*1=26kg/kmol

n=m/M=2/26=0,076923 kmoli C2H2 = 76,923 moli C2H2

1 mol C2H2......................6,023*10^23 particule
76,923 moli C2H2.............x=463,3*10^23 particule