Question

2.)Determina formula moleculara a achinei care contine 92,31% C si 7,69% iar masa molara M= 26.​

Answer 1

Raspuns

C: 92,31/12=7,69

H: 7,69/1=7,69

C: 7,69/7,69=1

H: 7,69/7,69=1

F.B =(CH)n n= M/(12+1) ; n=26/13=1

F.M = C2H2 etina sau acetilena

M-masa molara

F.B formula bruta

F.M formula moleculara

A (C)=12- masa atomica carbon

A(H)=1- masa atomica hidrogen

/ operatie de impartire