Question

2. Efectuați:
a) (x+6) ^2
b) (3a -1)^2
c) (3y - 2)(3y + 2):
d) (4x + 3y) (4x - 3y).​

Answer 1

a)(x+6)^2

=x^2+2x×6+6^2

=x^2+12x+6^2

=x^2+12x+36

b)(3a-1)^2

=(3a)^2-2×3a×1+1^2

=9a^2-2×3a×1+1^2

=9a^2-6a+1^2

=9a^2-6a×1

c)(3y-2)(3y+2)

=(3y)^2-2^2

=9y^2-2^2

=9y^2-4

d)(4x+3y)(4x-3y)

=(4x)^2-(3y)^2

=16x^2-(3y)^2

=16x^2-9y^2

Answer 2

Răspuns:

vezi poza

Explicație pas cu pas: