Matematică, întrebare adresată de turcurares176, 7 ani în urmă

2 Efectuează: ta) 10 x 100 (864:2+ 336:3+ 1296: 4) = b) (777:7+464:2-969:3+888:4):2-194:2= TC) (468:2+ 848:4+ 646:2+ 666:6) + 10:5= Td) (848:4-448:4+696:3+ 402:3): 2x3 = te) 17 x 20- (968: 4+963:3+ 866:2):3 = f) (550:5+932:4 +686: 2):2-111 x 3 = g) 61 x 10- (4682 +848:2 +999:9 +444:4):2:2 = h) 15 x 25 (972:3 +222:2 +462:2 +999: 3) : 3 = i) (425:5+ 129 x 4 + 2):3x4-127 x 6+2 x 29 = j) 144:3x9- (57 x 8-97 x 4 + 824:4+39 x 4) = k) (543:3+ 171:9):5+ (651:3+3 x 128 + 400: 100):5= I) 4+ 129 x 4-(621:3-108:9-300 : 4) = m) 1+ (705:5+381:3 x 2): 5-576:9= n) 153:9+ (148 x 4-852:3):4-4 × 16 = o) 384:8+ (295 x 3- 742:7+1): 3:5-588:6= p) 3x5-3x6:(3x3x3:3+0:5) + 30: (3:3+5) = - RO 2​

Anexe:

Răspunsuri la întrebare

Răspuns de 2ancadumitrescu
2

Efectuează:

a) 10 x 100 - (864:2+ 336:3+ 1296: 4) =

1000 - (432 + 112 + 324) =

1000 - 868 = 132

b) (777:7+464:2-969:3+888:4):2-194:2=

(111 + 232 - 323 + 222) : 2 - 97 =

(343 - -323 + 222) : 2 - 97 =

(20 + 222) :2 - 97 =

242 : 2 - 97 =

121 - 97 = 24

C) (468:2+ 848:4+ 646:2+ 666:6) + 10:5=

234 + 212 + 323 + 111 + 2 = 882

d) (848:4-448:4+696:3+ 402:3): 2x3 =

(212 - 112 + 232 + 134) : 2 x 3 =

(100+232+134) : 2 x 3 =

466 : 2 x 3 =

233 x 3 = 699

e) 17 x 20- (968: 4+963:3+ 866:2):3 =

340 - ( 242 + 321 + 433) : 3 =

340 - 996 : 3 =

340 - 332 = 8

f) (550:5+932:4 +686: 2):2-111 x 3 =

(110 + 233 + 343 ) : 2 - 333 =

686 : 2 - 333 =

343 - 333= 10

g) 61 x 10- (468:2 +848:2 +999:9 +444:4):2:2 =

610 - ( 234 + 424 + 111 + 111) : 2 : 2=

610 - 880 : 2 : 2=

610 - 440 : 2 =

610 - 220 = 390

h) 15 x 25- (972:3 +222:2 +462:2 +999: 3) : 3 =

375 - (324 + 111+231+333) : 3 =

375 - 999 : 3 =

375 - 333 = 42

i) (425:5+ 129 x 4 + 2):3x4-127 x 6+2 x 29 =

(85 + 516 + 2) : 3 x 4 - 762 + 58 =

603 : 3 x 4 - 762 + 58 =

201 x 4 - 762 + 58=

804  - 762 + 58 =

42 + 58 = 100

j) 144:3x9- (57 x 8-97 x 4 + 824:4+39 x 4) =

48 x9 - ( 456-388+206+156)=

432 - (68+206+156)=

432 - 430 = 2

k) (543:3+ 171:9):5+ (651:3+3 x 128 + 400: 100):5=

(181+19):5 + (217+384+4):5=

200:5 + 605:5=

40+121=161

I) 4+ 129 x 4-(621:3-108:9-300 : 4) =

4+516-(207-12-75)=

520-120=400

m) 1+ (705:5+381:3 x 2): 5-576:9=

1+(141+127x2):5-64=

1+(141+254):5 -64=

1+395:5-64=

1+79-64=

80-64=16

n) 153:9+ (148 x 4-852:3):4-4 × 16 =

17 + (592-284):4-64=

17+308 : 4-64=

17+77-64=30

o) 384:8+ (295 x 3- 742:7+1): 3:5-588:6=

48 + (885-106+1):3:5-98=

48+780:3:5-98=

48+260:5-98=

48+52-98=

100-98=2

p) 3x5-3x6:(3x3x3:3+0:5) + 30: (3:3+5) =

15 - 18 : (9+0) + 30:(1+5)=

15-18:2+30:6=

15-9+5=

6-5=1


turcurares176: am vrut până la punctul p)
turcurares176: va rog dați-mi răspuns îmi trebuie pentru mâine
2ancadumitrescu: Ok. In imagine , aparea T doar pâna la e)
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