Question

2(întregi)5/6-[2,(36)x2,(4)-1(întreg)7/55x1,(2)+30,2]x2,5

Answer 1

2intreg 5/6=(2x6+5)/6=17/6
2,(36)=(236-2)/99=234/99=78/33=26/11
2,(4)=(24-2)/9=22/9
1intreg7/55=(1x55+7)/55=62/55
1,(2)=(12-1)/9=11/9
30,2=302/10=151/5
2,5=25/10=5/2
17/6-[26/11x22/9-62/55x11/9+151/5]x5/2=
17/6-(52/9-62/495)x5/2=
17/6-[(52x55-62)/495]x5/2=
17/6-[(2860-62)/495]x5/2=
17/6-2798/495x5/2=
17/6-1399/99=(17x33-1399x2)/198=
(561-2798)/198=-2237/198=-11,2(97)