Question

2 la puterea 100:[2 la puterea 50 ori 2 la puterea 48 (2 la puterea 10 ori 2 la puterea 15)la puterea 5 : 2 la puterea 27 + (5 la puterea 76/5 la puterea 75 --3 )la puterea 90 *2 la puterea 8 + 2 la puterea 98]

Answer 1

2^100:[2^50×2^48(2^10×2^15)^5:2^27+(5^76 : 5^75 - 3)^90×2^8 + 2^98] =

= 2^100:[2^98(2^25)^5:2^27+(5-3)^90×2^8+2^98] =

= 2^100:[2^98×2^125:2^27+2^90×2^8+2^98] =
= 2^100:[2^98×2^98+2^98+2^98] =

= 2^100:2^98×(2^98+1+1) =
= 2^109:2^98×(2^98+2) =
= 2^11 ×( 2^98+2) =
= 2^108 + 2^12