Question

2 la puterea 2000 supra 2 la puterea 1998+2 la puterea 1995 ori 5 la puterea 2-4 la puterea 2 supra 2 la 7 - 2 la 3

Answer 1

$\frac{ {2}^{2000} }{ {2}^{1995} } \times {5}^{2} - \frac{ {4}^{2} }{ {2}^{7} } - {2}^{3} = {2}^{5} \times {5}^{2} - \frac{ {2}^{4} }{ {2}^{7} } - {2}^{3} = 32 \times 25 - \frac{1}{8} - 8 = \frac{6335}{8}$