Question

2 la puterea 2002+ 4 la puterea 1001= 2 la puterea n​

Answer 1

${2}^{2002} + {4}^{1001} = {2}^{n} \\ {2}^{2002} + { ({2}^{2} )}^{1001} = {2}^{n} \\ =2 \times {2}^{2002} = {2}^{n} \\ {2}^{2003} = {2}^{n}$

deci n=2003

Answer 2

Explicație pas cu pas:

sper sa intelegi modul de calcul