Question

2 la puterea 2004+4la puterea 1002+8la puterea 668+16 la puterea 501=?

Answer 1

2^2004 + 4^1002 + 8^668 + 16^501 =

Transformi bazele ca puteri la a 2-a

2^2004 + (2^2)^1002 + (2^3)^668 + (2^4)^501 =

2^2004 + 2^2004 + 2^2004 + 2^2004 =

2^2004(1+1+1+1) =

2^2004 x 4 =

2^2004 x 2^2 =

2^2006