Question

(2 la puterea 2011 x 4 la puterea 1005):[(22 la puterea a2a) la puterea a5a] la puterea 201

Answer 1

$( {2}^{2011} \times {4}^{1005} ) \div (({ { {2}^{2} })^{5} })^{201}$
$({2}^{2011} \times {( {2}^{2}) }^{1005} ) \div {2}^{2010}$

${2}^{4021} \div {2}^{2010} = {2}^{2011}$
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