Question

2 la puterea 2019 + 2 la puterea 2020 + 2 la puterea 2021/x=32 la puterea 404/0,5,x nu este egal cu 0.Dau coroana!!!!

Answer 1

Explicație pas cu pas:

$\frac{ {2}^{2019} + {2}^{2020} + {2}^{2021} }{x} = \frac{ {32}^{404} }{0.5} \\ \frac{ {2}^{2019} \cdot (1 + 2 + {2}^{2})}{x} = \frac{ {( {2}^{5} )}^{404} }{ \frac{1}{2} } \\ \frac{ {2}^{2019} \cdot (3 + 4)}{x} = {2}^{5 \cdot 404} \cdot 2 \\ \frac{ {2}^{2019} \cdot 7}{x} = {2}^{2021}\iff x = \frac{{2}^{2019} \cdot 7}{{2}^{2021}} \\ x = \frac{7}{ {2}^{2} } \iff x = \frac{7}{4}$