Question

2 la puterea 21:[(3la puterea 3×5÷15+7 la puterea 0) totul la 5÷10 la puterea 3-6la puterea 2]totul la 3+79

Answer 1

2^21:[(27×1/3+1)^5÷1000-36]^3+ 79=2^21:(10^5:1000-36)^3+79= 2^21:(100-36)^3+79= 2^21:64^3+79= 2^21:(8^2)^3+79 = 2^21:8^6+79=2^21:(2^3)^6+79 =2^21:2^18+79= 2^(21-18)+79= 2^3+79=8+79=87.