Question

| 2 la puterea 33 - 3 la puterea 22 | + 8 la puterea 11 = ?

Answer 1

[tex]2^{33}=(2^3)^{11} \\ 3^{22}=(3^{2})^{11} \\ 3^{2}\ \textgreater \ 2^{3}=\ \textgreater \ 2^{33}\ \textless \ 3^{22} \\ |2^{33}-3^{22}|+8^{11}= \\ -2^{33}+3^{22}+(2^{3})^{11}= \\ 3^{22}+2^{33}-2^{33}=3^{22} [/tex]