Question

2 la puterea a 53-a comparat la 4 la puterea a 29-a. Repede răspuns plus explicare.

Answer 1

$4^{29}=(2^2)^{29}=2^{58}\\2^{53}<2^{58}\\2^{53} < 4^{29}$

Answer 2

4^29 = > (2^2)^29 = > 2^ 58

bazele sunt egale 2 = 2 , deci comparam exponentii   53 < 58

2^53 <  4^29