Question

2 la puterea a treia ori 8 la puterea a patra ori 16 la puterea a cincea ori 32 la puterea a șasea​

Answer 1

Răspuns:

Explicație pas cu pas:

$\Big 2^3*\Big 8^{4}*\Big {16}^5 *\Big {32}^6 = \\\\=\Big 2^3*\Big (\Big 2^3\Big)^4 *\Big (\Big 2^4\Big)^5 *\Big (\Big 2^5\Big)^6 = \\\\\\=\Big 2^3*\Big 2^{3*4}*\Big 2^{4*5}*\Big 2^{5*6} = \\\\=\Big 2^3*\Big 2^{12}*\Big 2^{20}*\Big 2^{30} = \\\\=\Big 2^{\Big {3 + 12 + 20 +30}} = \\\\=\Big 2^{\Big {65}}$

Answer 2

$\it 2^3\cdot8^4\cdot16^5\cdot32^6=2^3\cdot(2^3)^4\cdot(2^4)^5\cdot(2^5)^6=2^3\cdot2^{12}\cdot2^{20}\cdot2^{30}=\\ \\ =2^{3+12+20+30}=2^{65}$