Question

2 la puterea n plus 2 plus 2 la puterea n plus unu plus doi la puterea n împărțit la 2 la puterea n minus 5​

Answer 1

Răspuns:

$({2}^{n + 2} + {2}^{n + 1} + {2}^{n} )\div {2}^{n - 5} = {2}^{n} ( {2}^{2} + 2 + 1) \div {2}^{n} \div {2}^{5} = \frac{7}{32}$