Question

( 2 minus radical din 3)^2012 inmultit cu ( 7+ 4 radical din 3)^ 1006

Answer 1

4√3=2ab|:2
2√3=ab
a=2
b=√3
(a+b)^2=a^2+2ab+b^2
deci 7+4√3=4+4√3+3=(2+√3)^2
(2-√3)^2012×(2+√3)2×1006=
(2-√3)^2012×(2+√3)2012=
[(2-√3)(2+√3)]^2012
(4-3)2012=1^2012=1
^ l -am utilizat pt putere