Question

(2^n+1 ×3^n+2^n×3^n+2)se divide cu 11

Answer 1

ai rezolvarea în imagine

Answer 2

$2^{n+1}*3^{n}+2^{n}*3^{n+2}=2^{n}*2*3^{n}+2^{n}*3^{n}*3^{2}=$

$=2^{n}*3^{n} (2+3^{2})=$

$=(2*3)^{n} (2+9)=$

$=6^{n}*11$, se divide cu 11