Question

{[(2×n-3)×5+7]:51+3}×2=10​

Answer 1

Răspuns: $\bf \purple{ \underline{n =11}}$

Explicație pas cu pas:

Folosim metoda mersului invers pentru a rezolva exercițiul

$\bf \big\{[(2 \cdot n-3) \cdot5+7]:51+3 \big\} \cdot2=10$

$\bf \big\{[(2 \cdot n-3) \cdot5+7]:51+3 \big\}=10 : 2$

$\bf \big[(2 \cdot n-3) \cdot5+7\big]:51+3=5$

$\bf \big[(2 \cdot n-3) \cdot5+7\big]:5=5 - 3$

$\bf \big[(2 \cdot n-3) \cdot5+7\big]:51=2$

$\bf \big[(2 \cdot n-3) \cdot5+7\big]=2 \cdot51$

$\bf \big(2 \cdot n-3\big) \cdot5+7=102$

$\bf \big(2 \cdot n-3\big) \cdot5=102 - 7$

$\bf \big(2 \cdot n-3\big) \cdot5=95$

$\bf \big(2 \cdot n-3\big) =95 : 5$

$\bf 2 \cdot n-3 =19$

$\bf 2 \cdot n =19 + 3$

$\bf 2 \cdot n =22$

$\bf n =22 : 2$

$\bf \purple{ \underline{n =11}}$

==pav38==

Baftă multă !