Question

(2/radical din 12-15/5 radical din 3+9/radical din 27)-(24/radical din 48+45/radical din 75+48/8 radical din 3)

Answer 1

Răspuns

$\frac{2}{\sqrt{12} } - \frac{15}{5} \sqrt{3} + \frac{9}{\sqrt{27} }  = \sqrt{12}  - 3\sqrt{3}  + \sqrt{3} = 2\sqrt{3} \\\frac{24}{\sqrt{48} } +\frac{45}{\sqrt{75} }  + \frac{48}{8} \sqrt{3} =  2\sqrt{3} + 3\sqrt{3} + 6 \sqrt{3}   = 11 \sqrt{3}\\ 2\sqrt{3} - 11\sqrt{3} = -9 \sqrt{3}$