Question

2 radical din 18 + radical din 50 - 3 radical din 32

Answer 1

= 2×3√2 + 5√2- 3×4√2 =

= 6√2 + 5√2 - 12√2 =

= 11√2 - 12√2 =

= - √2

Answer 2

$2 \sqrt{18} + \sqrt{50} - 3 \sqrt{32} = \\ \\ 2 \times 3 \sqrt{2} + 5 \sqrt{2} - 3 \times 4 \sqrt{2} = \\ \\ 6 \sqrt{2} + 5 \sqrt{2} - 12 \sqrt{2} = \\ \\ - \sqrt{2}$