Question

|2-radical din 3| + 1 supra 2-radical din 3
Help me..

Answer 1

$\displaystyle |2- \sqrt{3} |+ \frac{1}{2} - \sqrt{3} =2- \sqrt{3} + \frac{1}{2} - \sqrt{3} =2-2 \sqrt{3} + \frac{1}{2}= \\ \\ = \frac{4-4 \sqrt{3} +1}{2} = \frac{5-4 \sqrt{3} }{2}$