Question

2 radical din 6 ori 4 radical din 3 ori (-1)

Answer 1

$2 \sqrt{6} \times 4 \sqrt{3} \times ( - 1) = 2 \times 4 \times ( - 1) \sqrt{6 \times 3} = \\ = - 8 \sqrt{18} = - 8 \sqrt{ {3}^{2} \times 2} = - 8 \times 3 \sqrt{2} = \\ = - 24 \sqrt{2}$