Question

2 radical din 75 - 2 radical din 12 - radical din 27 + radical din 48 ​

Answer 1

$\it 2\sqrt{75}-2\sqrt{12}-\sqrt{27}+\sqrt{48}=\sqrt3(2\sqrt{25}-2\sqrt4-\sqrt9+\sqrt{16})=\\ \\ =\sqrt3(10-4-3+4)=7\sqrt3$

Answer 2

Explicație pas cu pas:

$2 \sqrt{75} - 2 \sqrt{12} - \sqrt{27} + \sqrt{48} =$

$= 2 \sqrt{3 \cdot {5}^{2} } - 2 \sqrt{ {2}^{2} \cdot 3} - \sqrt{ {3}^{3} } + \sqrt{ {2}^{4} \cdot 3}$

$= 2 \cdot 5 \sqrt{3} - 2 \cdot 2 \sqrt{3} - 3 \sqrt{3} + {2}^{2} \sqrt{3}$

$= 10 \sqrt{3} - 4 \sqrt{3} - 3 \sqrt{3} + 4 \sqrt{3}$

$= 14 \sqrt{3} - 7 \sqrt{3} = \bf 7 \sqrt{3}$