Question

2-radical3 supra radical3

Answer 1

$\frac{2-\sqrt{3}}{\sqrt{3}}=$

$=\frac{\sqrt{3}(2-\sqrt{3})}{\sqrt{3}*\sqrt{3}}=$

$=\frac{2\sqrt{3}-3}{3}=$

$=\frac{2\sqrt{3}}{3}-\frac{3}{3}$

$=\frac{2\sqrt{3}}{3}-1$