Question

2) Rezolvati : A) (2+radical din 3) la 2

Answer 1

(2+rad3)^2=2^2+2×2× rad 3 + rad 3^2= 4+4 rad 3 + 3 = 7 + 4 radical din 3. Greseala mea.....

Answer 2

${(2 + \sqrt{3} )}^{2} = {2}^{2} + 2 \times 2 \times \sqrt{3} + {( \sqrt{3} )}^{2}$

$= 4 + 4 \sqrt{3} + 3$

$= 7 + 4 \sqrt{3}$

$Formul\check{a}\:: \: {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$