Question

2. Rezolvaţi în R ecuatia:
a) 3(x-1)= x+2; b) 3(x - 1) = 5x+2;
d) 5(x+3) = 10; e) 3(2x + 7) = 9;
9) 4(x-2)=-6; h) 2² +3(x+5)=x+8;
1) 3(2x-1) +4= 7; k) 2(x+1) = 3(x-1);
c) 3(x-2)=4x;
1) 212-x)=x-5;
12(x-1) -5x = 18-7x;
1) 2(x+3)+3x = 5(x+2).​

Answer 1

Explicație pas cu pas:

a) 3(x-1)=x+2

3x-3=x+2

3x-x=2+3

2x=5

x=5/2

b) 3(x-1)=5x+2

3x-3=5x+2

3x-5x=2+3

-2x=5

x=-5/2

d) 5(x+3)=10

x+3=2

x=2-3

x=-1

e) 3(2x+7)=9

2x+7=3

2x=3-7

2x=-4

x=-2

9) 4(x-2)=-6

4x-8=-6

4x=-6+8

4x=2

x=1/2

h) 2^2+3(x+5)=x+8

4+3x+15=x+8

19+3x=x+8

3x-x=8-19

2x=-11

x=-11/2

1) 3(2x-1)+4=7

6x-3+4=7

6x+1=7

6x=7-1

6x=6

x=1

k) 2(x+1)=3(x-1)

2x+2=3x-3

2x-3x=-3-2

-x=-5

x=5

c) 3(x-2)=4x

3x-6=4x

3x-4x=6

-x=6

x=-6

1) 212-x=x-5

-x-x=-5-212

-2x=-217

x=217/2

12(x-1)-5x=18-7x

12x-12-5x=18-7x

7x-12=18-7x

7x+7x=18+12

14x=30

x=15/7

1) 2(x+3)+3x=5(x+2)

2x+6+3x=5x+10

5x+6=5x+10

6=10

Afirmația este falsă

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