Question

2. Sa se rezolve in Q
a) 13x=-182
b) -0,5x=-8
c)-0,16x=3,2
d)-0,5=2
e)4,8x=-9,6
f) x:(-3)=6
g)x:4=-20
h)-15:x=13
i)16:x=-8
j) (x+3) :2=-8
k) (4x+8):(-4)=5
l) -3x=0

Answer 1

$13x = - 182 \\ x = - \frac{ 182}{13} \\ x = - 14$

$- 0.5x = - 8 \\ - \frac{5}{10} x = - 8 \\ - \frac{1}{2} x = - 8 \\ x = 8 \times \frac{2}{1} \\ x = 16$

$- 0.16x = 3.2 \\ - \frac{16}{100} x = \frac{32}{10} \\ - \frac{4}{25} x = \frac{16}{5} \\ x = \frac{16}{5} \times ( - \frac{25}{4} ) \\ x = \frac{4}{1} \times ( - \frac{5}{1} ) \\ x = - 20$

$- 0.5 x= 2 \\ - \frac{5}{10}x = 2 \\ x = \frac{2}{1} \times ( - \frac{10}{5} ) \\ x = - \frac{20}{5} \\ x = - \frac{4}{1} \\ x = - 4$

$4.8x = - 9.6 \\ \frac{48}{10} x = - \frac{96}{10} \\ \frac{24}{5} x = - \frac{48}{5} \\ x = - \frac{48}{5} \times \frac{5}{24} \\ x = - \frac{2}{1} \times \frac{1}{1} \\ x = - 2$

$x \div ( - 3) = 6 \\ x = 6 \times ( - 3) \\ x = - 18$

$x \div 4 = - 20 \\ x = - 20 \times 4 \\ x = - 80$

$- 15 \div x = 13 \\ x = - \frac{15}{13}$

$16 \div x = - 8 \\ x = - \frac{16}{8} \\ x = - \frac{2}{1} \\ x = - 2$

$(x + 3) \div 2 = - 8 \\ x + 3 = - 8 \times 2 \\ x + 3 = - 16 \\ x = - 19$

$(4x + 8) \div ( - 4) = 5 \\ 4x + 8 = 5 \times ( - 4) \\ 4x + 8 = - 20 \\ 4x = - 28 \\ x = - \frac{28}{4} \\ x = - \frac{7}{1} \\ x = - 7$

$- 3x = 0 \\ x = - \frac{0}{3} \\ x = 0$